Correct me if I'm wrong, but if you have a 1% error rate (for example), then wouldn't quantum computers need to be at least 2x as powerful as current ones, as you need to perform each computation at least twice to confirm the end result is correct? Because speaking as a SW Engineer: 1% error rate is enough to make sure your PC doesn't even boot, let alone get you to your desktop.
I could be wrong, but given that there's the inherent possibility that a quantum computer will get the solution to a problem wrong, I don't know that a standard benchmark could work. I mean, we have a benchmark for what CPUs are capable of because we have the basic understanding that it's always going to be correct, it's just a question of how long it takes to get there. With quantum computing introducing the variable of incorrect answers, you have to take that into account. Maybe you can run the benchmark you're talking about 100 times and average the results, but I think this idea of quantum volume is a simpler - or at least faster - way of looking at capability.I can certainly understand the observation that understanding the relative performance of different quantum computers can be difficult.
However, this is something that conventional computing solved quite some time ago: it's called a benchmark.
Extrapolating, could we not develop a small selection of Q-computing-relevant problems and have each Q-computer tackle them? I appreciate that single problem is unreasonable given the anticipation of slightly different design priorities. However, a range of [for example] cryptographic problems to factor might present us with a workable model.
Ultimately, the value of a Q-computer to the world at large will be derived from the ability of that computer to solve world-relevant problems. A generic benchmark seems like a workable approach.
Am I missing something?
I agree with Niwax. It seems like future traditional computers will have quantum add-ons (sort of like graphics cards) for these type of computations. You wouldn't want to rely on them for loading the whole OS or dealing with sensitive files, where even a 0.001% error rate could be catastrophic.
I'll be the first to admit that I think quantum computing exists solely for the purpose of making my brain hurt.
Some bar graphs illustrating the projected limits of computer speed would've been nice.
— A measurement without units is, in my opinion, a measurement we don't understand. It's frequently a fudge-factor, or, an excuse for not fully understanding the shape & size, or the dimensions of the problem we are trying to solve.…a 30-qubit system with no gate errors has a quantum volume of 900 (no units for this).
— What is an "operation" in quantum-computing land? Where is this explained? This could just be my ignorance here…two-qubit operation
Unfortunately, if you compare the calculated error rate, the number of qubits and the quantum volume, the results are inconsistent. We've reached out to IBM and will update when they respond.
Simulated annealing is a very nice concept, but simulated annealing is what D-Wave's pseudo-quantum-computer is doing. A general purpose quantum computer is more powerful and does not rely on annealing. As far as I understand it, this new IBM system is a general purpose quantum computer.I'll be the first to admit that I think quantum computing exists solely for the purpose of making my brain hurt.
Some bar graphs illustrating the projected limits of computer speed would've been nice.
There are some lovely easy to understand aspects though. My favorite is this one: An interesting property of ice is that its molecules are almost perfectly optimally ordered due to the gradual effects during the cooling process that allow smaller and smaller optimizations. By applying the same gradually smaller steps to traditional optimization problems, simulated annealing was created. We have now come full circle and implement those algorithms by wiring a quantum computer to represent the problem and actually cooling it down.
Simulated annealing is a very nice concept, but simulated annealing is what D-Wave's pseudo-quantum-computer is doing. A general purpose quantum computer is more powerful and does not rely on annealing. As far as I understand it, this new IBM system is a general purpose quantum computer.I'll be the first to admit that I think quantum computing exists solely for the purpose of making my brain hurt.
Some bar graphs illustrating the projected limits of computer speed would've been nice.
There are some lovely easy to understand aspects though. My favorite is this one: An interesting property of ice is that its molecules are almost perfectly optimally ordered due to the gradual effects during the cooling process that allow smaller and smaller optimizations. By applying the same gradually smaller steps to traditional optimization problems, simulated annealing was created. We have now come full circle and implement those algorithms by wiring a quantum computer to represent the problem and actually cooling it down.
There are quantities that are truly unitless, because units can be multiplied and divided like numbers and for some quantities the units simply cancel out. For example the fine-structure constant is unitless (which is very helpful - it will have the same numerical value in all measurement systems). Also angles are unitless (length of arc divided by length of radius).— A measurement without units is, in my opinion, a measurement we don't understand. It's frequently a fudge-factor, or, an excuse for not fully understanding the shape & size, or the dimensions of the problem we are trying to solve.…a 30-qubit system with no gate errors has a quantum volume of 900 (no units for this).
It is basically multiplication of a complex vector that represents the internal state of the quantum computer by a complex matrix (a unitary matrix, if i remember correctly). That's what I recollect from the introductory quantum computing course I took in university.— What is an "operation" in quantum-computing land? Where is this explained? This could just be my ignorance here…two-qubit operation
I agree with Niwax. It seems like future traditional computers will have quantum add-ons (sort of like graphics cards) for these type of computations. You wouldn't want to rely on them for loading the whole OS or dealing with sensitive files, where even a 0.001% error rate could be catastrophic.
I wonder if they'll every make a hybrid board that supports the traditional CPU along with a built-in Quantum chip rather than a PCI slot?
I can certainly understand the observation that understanding the relative performance of different quantum computers can be difficult.
However, this is something that conventional computing solved quite some time ago: it's called a benchmark.
Extrapolating, could we not develop a small selection of Q-computing-relevant problems and have each Q-computer tackle them? I appreciate that single problem is unreasonable given the anticipation of slightly different design priorities. However, a range of [for example] cryptographic problems to factor might present us with a workable model.
Ultimately, the value of a Q-computer to the world at large will be derived from the ability of that computer to solve world-relevant problems. A generic benchmark seems like a workable approach.
Am I missing something?
There are quantities that are truly unitless, because units can be multiplied and divided like numbers and for some quantities the units simply cancel out. For example the fine-structure constant is unitless (which is very helpful - it will have the same numerical value in all measurement systems). Also angles are unitless (length of arc divided by length of radius).— A measurement without units is, in my opinion, a measurement we don't understand. It's frequently a fudge-factor, or, an excuse for not fully understanding the shape & size, or the dimensions of the problem we are trying to solve.…a 30-qubit system with no gate errors has a quantum volume of 900 (no units for this).
It is basically multiplication of a complex vector that represents the internal state of the quantum computer by a complex matrix (a unitary matrix, if i remember correctly). That's what I recollect from the introductory quantum computing course I took in university.— What is an "operation" in quantum-computing land? Where is this explained? This could just be my ignorance here…two-qubit operation
Edit: spelling
Where is this "newly announced" 17-qubit device? Why is there no link? Google isn't finding any announcements. On IBM's website, I don't see any news posted, and you are still limited to 5-qubit experiments.
There are a lot of Dimensionless Quantities that have real meaning.— A measurement without units is, in my opinion, a measurement we don't understand. It's frequently a fudge-factor, or, an excuse for not fully understanding the shape & size, or the dimensions of the problem we are trying to solve.…a 30-qubit system with no gate errors has a quantum volume of 900 (no units for this).
I'm afraid that your explanation is partly beyond me, but based on the part I understand (and the studies I've done), I might suggest that even unitless quantities are not always dimensionless, directionless and scalar. For example, even if you divide seconds by seconds, you still end up with a proportion of time — and it can still be useful to retain that conceptual label on a quantity that at face value, represents nothing more than a raw number![url=https://arstechnica.co.uk/civis/viewtopic.php?p=33341855#p33341855:332mkoxh said:cse84[/url]":332mkoxh]There are quantities that are truly unitless, because units can be multiplied and divided like numbers and for some quantities the units simply cancel out. For example the fine-structure constant is unitless (which is very helpful - it will have the same numerical value in all measurement systems). Also angles are unitless (length of arc divided by length of radius).— A measurement without units is, in my opinion, a measurement we don't understand. It's frequently a fudge-factor, or, an excuse for not fully understanding the shape & size, or the dimensions of the problem we are trying to solve.…a 30-qubit system with no gate errors has a quantum volume of 900 (no units for this).
It is basically multiplication of a complex vector that represents the internal state of the quantum computer by a complex matrix (a unitary matrix, if i remember correctly). That's what I recollect from the introductory quantum computing course I took in university.— What is an "operation" in quantum-computing land? Where is this explained? This could just be my ignorance here…two-qubit operation
Edit: spelling
I agree that a dimensionless number still has a meaning that is not interchangeable with the meaning of other dimensionless numbers. Unfortunately many theoretical physicists leave out units and even many constant factors because of the convenience of having a shorter, easier to read (for an expert in the field at least) formula - you might call that laziness instead of convenience, if you like. It might also have to do with the fact that all of our measurement systems choose their units more or less arbitrarily.I'm afraid that your explanation is partly beyond me, but based on the part I understand (and the studies I've done), I might suggest that even unitless quantities are not always dimensionless, directionless and scalar. For example, even if you divide seconds by seconds, you still end up with a proportion of time — and it can still be useful to retain that conceptual label on a quantity that at face value, represents nothing more than a raw number![url=https://arstechnica.co.uk/civis/viewtopic.php?p=33341855#p33341855:2z1e3h34 said:cse84[/url]":2z1e3h34]There are quantities that are truly unitless, because units can be multiplied and divided like numbers and for some quantities the units simply cancel out. For example the fine-structure constant is unitless (which is very helpful - it will have the same numerical value in all measurement systems). Also angles are unitless (length of arc divided by length of radius).— A measurement without units is, in my opinion, a measurement we don't understand. It's frequently a fudge-factor, or, an excuse for not fully understanding the shape & size, or the dimensions of the problem we are trying to solve.…a 30-qubit system with no gate errors has a quantum volume of 900 (no units for this).
It is basically multiplication of a complex vector that represents the internal state of the quantum computer by a complex matrix (a unitary matrix, if i remember correctly). That's what I recollect from the introductory quantum computing course I took in university.— What is an "operation" in quantum-computing land? Where is this explained? This could just be my ignorance here…two-qubit operation
Edit: spelling
So even with your explanation, this is still tripping my "scientific snake-oil" detector — since too many quantities in this article are essentially unitless, or heuristically assigned some nebulous conceptual unit…
Some of this gap in understanding comes down to a lack of necessary education on my part. However, I do believe that a lot of progress in mathematics and physical sciences may be made through reforms that emphasize the application of units and unit-like dimensional and directional (perhaps i-j-k style or polar-equivalent) annotations…
Perhaps. But with many such quantities, it could be argued that they are only "dimensionless" because our current system of units & dimensions is inadequate… Interestingly, each of these "dimensionless quantities" has a name — one might even use this name effectively as a unit, in a system which has rules for combining them (where the rules might be governed partly by consideration of these units as "compound units"). The adequacy or inadequacy of a system of units, might be determined by the requirements of the application…[url=https://arstechnica.co.uk/civis/viewtopic.php?p=33342143#p33342143:hpqljkj6 said:tricorn[/url]":hpqljkj6]There are a lot of Dimensionless Quantities that have real meaning.— A measurement without units is, in my opinion, a measurement we don't understand. It's frequently a fudge-factor, or, an excuse for not fully understanding the shape & size, or the dimensions of the problem we are trying to solve.…a 30-qubit system with no gate errors has a quantum volume of 900 (no units for this).
Agreed — in part, this was my point — that "unitless" does not imply "scalar", nor does it imply interchangeability with other "unitless" quantities.[url=https://arstechnica.co.uk/civis/viewtopic.php?p=33342317#p33342317:hpqljkj6 said:cse84[/url]":hpqljkj6]I agree that a dimensionless number still has a meaning that is not interchangeable with the meaning of other dimensionless numbers. Unfortunately many theoretical physicists leave out units and even many constant factors because of the convenience of having a shorter, easier to read (for an expert in the field at least) formula - you might call that laziness instead of convenience, if you like. It might also have to do with the fact that all of our measurement systems choose their units more or less arbitrarily.I'm afraid that your explanation is partly beyond me, but based on the part I understand (and the studies I've done), I might suggest that even unitless quantities are not always dimensionless, directionless and scalar. For example, even if you divide seconds by seconds, you still end up with a proportion of time — and it can still be useful to retain that conceptual label on a quantity that at face value, represents nothing more than a raw number![url=https://arstechnica.co.uk/civis/viewtopic.php?p=33341855#p33341855:hpqljkj6 said:cse84[/url]":hpqljkj6]There are quantities that are truly unitless, because units can be multiplied and divided like numbers and for some quantities the units simply cancel out. For example the fine-structure constant is unitless (which is very helpful - it will have the same numerical value in all measurement systems). Also angles are unitless (length of arc divided by length of radius).— A measurement without units is, in my opinion, a measurement we don't understand. It's frequently a fudge-factor, or, an excuse for not fully understanding the shape & size, or the dimensions of the problem we are trying to solve.…a 30-qubit system with no gate errors has a quantum volume of 900 (no units for this).
It is basically multiplication of a complex vector that represents the internal state of the quantum computer by a complex matrix (a unitary matrix, if i remember correctly). That's what I recollect from the introductory quantum computing course I took in university.— What is an "operation" in quantum-computing land? Where is this explained? This could just be my ignorance here…two-qubit operation
Edit: spelling
So even with your explanation, this is still tripping my "scientific snake-oil" detector — since too many quantities in this article are essentially unitless, or heuristically assigned some nebulous conceptual unit…
Some of this gap in understanding comes down to a lack of necessary education on my part. However, I do believe that a lot of progress in mathematics and physical sciences may be made through reforms that emphasize the application of units and unit-like dimensional and directional (perhaps i-j-k style or polar-equivalent) annotations…
By the way, being scalar or non-scalar is a concept that is different from having a unit of measurement or having none. You can have scalar quantities with or without units and you can have non-scalar quantities (i.e. vector/tensor/whatever quantities) with or without units. It is unfortunate that the term "dimensionless" is often used instead of "without measurement unit", because it can easily be confused with "scalar".
There are quantities that are truly unitless, because units can be multiplied and divided like numbers and for some quantities the units simply cancel out. For example the fine-structure constant is unitless (which is very helpful - it will have the same numerical value in all measurement systems). Also angles are unitless (length of arc divided by length of radius).— A measurement without units is, in my opinion, a measurement we don't understand. It's frequently a fudge-factor, or, an excuse for not fully understanding the shape & size, or the dimensions of the problem we are trying to solve.…a 30-qubit system with no gate errors has a quantum volume of 900 (no units for this).
It is basically multiplication of a complex vector that represents the internal state of the quantum computer by a complex matrix (a unitary matrix, if i remember correctly). That's what I recollect from the introductory quantum computing course I took in university.— What is an "operation" in quantum-computing land? Where is this explained? This could just be my ignorance here…two-qubit operation
Edit: spelling
Also, sometimes it just isn't necessary to include the units. I do however want to volunteer "Qberts" as the standardized unit for this measurement.
I think a 30 qubit system that attains a score of 900 Qberts is the goal here.
Where is this "newly announced" 17-qubit device? Why is there no link? Google isn't finding any announcements. On IBM's website, I don't see any news posted, and you are still limited to 5-qubit experiments.
Maybe because you searched for 17-qubit not 16?
https://phys.org/news/2017-05-ibm-power ... ssors.html
Where is this "newly announced" 17-qubit device? Why is there no link? Google isn't finding any announcements. On IBM's website, I don't see any news posted, and you are still limited to 5-qubit experiments.
Maybe because you searched for 17-qubit not 16?
https://phys.org/news/2017-05-ibm-power ... ssors.html
No, I saw that page. It also doesn't link to anything from IBM.
And if you go to IBM's page, they still only give you a five-qubit machine to play with, not 16. I think it is fairly useless.
Two new processors
IBM Q has successfully built and tested two of its most powerful universal quantum computing processors to date: 16 qubits for public use and a 17 qubit prototype commercial processor.
Where is this "newly announced" 17-qubit device? Why is there no link? Google isn't finding any announcements. On IBM's website, I don't see any news posted, and you are still limited to 5-qubit experiments.
Maybe because you searched for 17-qubit not 16?
https://phys.org/news/2017-05-ibm-power ... ssors.html
No, I saw that page. It also doesn't link to anything from IBM.
And if you go to IBM's page, they still only give you a five-qubit machine to play with, not 16. I think it is fairly useless.
https://www.research.ibm.com/ibm-q/
Two new processors
IBM Q has successfully built and tested two of its most powerful universal quantum computing processors to date: 16 qubits for public use and a 17 qubit prototype commercial processor.
I agree with Niwax. It seems like future traditional computers will have quantum add-ons (sort of like graphics cards) for these type of computations. You wouldn't want to rely on them for loading the whole OS or dealing with sensitive files, where even a 0.001% error rate could be catastrophic.
I wonder if they'll every make a hybrid board that supports the traditional CPU along with a built-in Quantum chip rather than a PCI slot?
Well given that all quantum processors operate at near absolute zero I doubt it. It doesn't take much thermal noise to flip a qubit. The idea that you will have a general PC with a quantum coprocessor is doubtful.
To give you an idea the tiny chip in the article photo is inside the giant cylinder in this photo. Most of that volume is insulation and successive layers of cryocoolers to bring the temp at the chip to near absolute zero. That entire rack of equipment to the right is the additional equipment needed to run the series of cryocoolers.
![]()
You may someday have your always online computer (even one that fits in your pocket) send a request off to a quantum computer in the cloud. Even that would require costs to come down by probably six orders of magnitude.
I agree with Niwax. It seems like future traditional computers will have quantum add-ons (sort of like graphics cards) for these type of computations. You wouldn't want to rely on them for loading the whole OS or dealing with sensitive files, where even a 0.001% error rate could be catastrophic.
Where is this "newly announced" 17-qubit device? Why is there no link? Google isn't finding any announcements. On IBM's website, I don't see any news posted, and you are still limited to 5-qubit experiments.
Maybe because you searched for 17-qubit not 16?
https://phys.org/news/2017-05-ibm-power ... ssors.html
No, I saw that page. It also doesn't link to anything from IBM.
And if you go to IBM's page, they still only give you a five-qubit machine to play with, not 16. I think it is fairly useless.
https://www.research.ibm.com/ibm-q/
Two new processors
IBM Q has successfully built and tested two of its most powerful universal quantum computing processors to date: 16 qubits for public use and a 17 qubit prototype commercial processor.
Thank you.
Where is this "newly announced" 17-qubit device? Why is there no link? Google isn't finding any announcements. On IBM's website, I don't see any news posted, and you are still limited to 5-qubit experiments.
Maybe because you searched for 17-qubit not 16?
https://phys.org/news/2017-05-ibm-power ... ssors.html
No, I saw that page. It also doesn't link to anything from IBM.
And if you go to IBM's page, they still only give you a five-qubit machine to play with, not 16. I think it is fairly useless.
https://www.research.ibm.com/ibm-q/
Two new processors
IBM Q has successfully built and tested two of its most powerful universal quantum computing processors to date: 16 qubits for public use and a 17 qubit prototype commercial processor.
I can certainly understand the observation that understanding the relative performance of different quantum computers can be difficult.
However, this is something that conventional computing solved quite some time ago: it's called a benchmark.
Extrapolating, could we not develop a small selection of Q-computing-relevant problems and have each Q-computer tackle them? I appreciate that single problem is unreasonable given the anticipation of slightly different design priorities. However, a range of [for example] cryptographic problems to factor might present us with a workable model.
Ultimately, the value of a Q-computer to the world at large will be derived from the ability of that computer to solve world-relevant problems. A generic benchmark seems like a workable approach.
Am I missing something?
Because quantum computer isn't classic computing. Speed is kinda irrelevant. Assuming error is kept under control and you have a large enough qubits you will solve problems no matter the complexity essentially instantly and never be able to solve problems beyond the limits of the system no matter how much time is given.
As an example IBM's 16 qubit computer (assumming error is reasonably low) could implement Shor's algorithm to factor the product of 16 bit primes essentially instantly. However it could never factor the product of 17 bit primes no matter how much time is given.
I can certainly understand the observation that understanding the relative performance of different quantum computers can be difficult.
However, this is something that conventional computing solved quite some time ago: it's called a benchmark.
Extrapolating, could we not develop a small selection of Q-computing-relevant problems and have each Q-computer tackle them? I appreciate that single problem is unreasonable given the anticipation of slightly different design priorities. However, a range of [for example] cryptographic problems to factor might present us with a workable model.
Ultimately, the value of a Q-computer to the world at large will be derived from the ability of that computer to solve world-relevant problems. A generic benchmark seems like a workable approach.
Am I missing something?
I think it isn't saying there isn't a unit per se. I think it is saying that there isn't a defined unit YET. That is, this is a proposal for a method that attempts to create a way to encompass a quantum computer into a single integer value so that you can compare two different computers. Currently, the "unit" is a single output number. If the process becomes somewhat accepted, the groups that accept it can propose to and agree upon a name for the unit (such as the afore-mentioned "Q*bert"). I mean, we call it a Joule, but what did Joule call it?Perhaps. But with many such quantities, it could be argued that they are only "dimensionless" because our current system of units & dimensions is inadequate… Interestingly, each of these "dimensionless quantities" has a name — one might even use this name effectively as a unit, in a system which has rules for combining them (where the rules might be governed partly by consideration of these units as "compound units"). The adequacy or inadequacy of a system of units, might be determined by the requirements of the application…[url=https://arstechnica.co.uk/civis/viewtopic.php?p=33342143#p33342143:18vaveay said:tricorn[/url]":18vaveay]There are a lot of Dimensionless Quantities that have real meaning.— A measurement without units is, in my opinion, a measurement we don't understand. It's frequently a fudge-factor, or, an excuse for not fully understanding the shape & size, or the dimensions of the problem we are trying to solve.…a 30-qubit system with no gate errors has a quantum volume of 900 (no units for this).
Agreed — in part, this was my point — that "unitless" does not imply "scalar", nor does it imply interchangeability with other "unitless" quantities.[url=https://arstechnica.co.uk/civis/viewtopic.php?p=33342317#p33342317:18vaveay said:cse84[/url]":18vaveay]I agree that a dimensionless number still has a meaning that is not interchangeable with the meaning of other dimensionless numbers. Unfortunately many theoretical physicists leave out units and even many constant factors because of the convenience of having a shorter, easier to read (for an expert in the field at least) formula - you might call that laziness instead of convenience, if you like. It might also have to do with the fact that all of our measurement systems choose their units more or less arbitrarily.I'm afraid that your explanation is partly beyond me, but based on the part I understand (and the studies I've done), I might suggest that even unitless quantities are not always dimensionless, directionless and scalar. For example, even if you divide seconds by seconds, you still end up with a proportion of time — and it can still be useful to retain that conceptual label on a quantity that at face value, represents nothing more than a raw number![url=https://arstechnica.co.uk/civis/viewtopic.php?p=33341855#p33341855:18vaveay said:cse84[/url]":18vaveay]There are quantities that are truly unitless, because units can be multiplied and divided like numbers and for some quantities the units simply cancel out. For example the fine-structure constant is unitless (which is very helpful - it will have the same numerical value in all measurement systems). Also angles are unitless (length of arc divided by length of radius).— A measurement without units is, in my opinion, a measurement we don't understand. It's frequently a fudge-factor, or, an excuse for not fully understanding the shape & size, or the dimensions of the problem we are trying to solve.…a 30-qubit system with no gate errors has a quantum volume of 900 (no units for this).
It is basically multiplication of a complex vector that represents the internal state of the quantum computer by a complex matrix (a unitary matrix, if i remember correctly). That's what I recollect from the introductory quantum computing course I took in university.— What is an "operation" in quantum-computing land? Where is this explained? This could just be my ignorance here…two-qubit operation
Edit: spelling
So even with your explanation, this is still tripping my "scientific snake-oil" detector — since too many quantities in this article are essentially unitless, or heuristically assigned some nebulous conceptual unit…
Some of this gap in understanding comes down to a lack of necessary education on my part. However, I do believe that a lot of progress in mathematics and physical sciences may be made through reforms that emphasize the application of units and unit-like dimensional and directional (perhaps i-j-k style or polar-equivalent) annotations…
By the way, being scalar or non-scalar is a concept that is different from having a unit of measurement or having none. You can have scalar quantities with or without units and you can have non-scalar quantities (i.e. vector/tensor/whatever quantities) with or without units. It is unfortunate that the term "dimensionless" is often used instead of "without measurement unit", because it can easily be confused with "scalar".
The upgraded 16 qubit chip is available via our SDK: The details are here: https://developer.ibm.com/code/2017/05/ ... iskit-sdk/
Where is this "newly announced" 17-qubit device? Why is there no link? Google isn't finding any announcements. On IBM's website, I don't see any news posted, and you are still limited to 5-qubit experiments.
At about 64 qubits current cryptology is dead. At 100x100 qubit arrays who know what will happen. AI? I certainly have no idea.
Maybe because you searched for 17-qubit not 16?
https://phys.org/news/2017-05-ibm-power ... ssors.html
No, I saw that page. It also doesn't link to anything from IBM.
And if you go to IBM's page, they still only give you a five-qubit machine to play with, not 16. I think it is fairly useless.
https://www.research.ibm.com/ibm-q/
Two new processors
IBM Q has successfully built and tested two of its most powerful universal quantum computing processors to date: 16 qubits for public use and a 17 qubit prototype commercial processor.
Thank you.