Simulations consistent with large masses, eccentric orbits, tilted spin axes of GW190521.
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Was this mass not within the event horizon to begin with? Or is there a mechanism by which 8 solar masses can leave the event horizon rapidly?The black holes merged to form a new, even larger black hole of about 142 solar masses, emitting the energetic equivalent of eight solar masses in the process
Was this mass not within the event horizon to begin with? Or is there a mechanism by which 8 solar masses can leave the event horizon rapidly?The black holes merged to form a new, even larger black hole of about 142 solar masses, emitting the energetic equivalent of eight solar masses in the process
I understand that these are very energetic; but I was of the impression that, other than hawking radiation (which doesn't technically *leave* the black hole) nothing returns to the universe from past the event horizon other than gravity.
Was this mass not within the event horizon to begin with? Or is there a mechanism by which 8 solar masses can leave the event horizon rapidly?The black holes merged to form a new, even larger black hole of about 142 solar masses, emitting the energetic equivalent of eight solar masses in the process
I understand that these are very energetic; but I was of the impression that, other than hawking radiation (which doesn't technically *leave* the black hole) nothing returns to the universe from past the event horizon other than gravity.
Was this mass not within the event horizon to begin with? Or is there a mechanism by which 8 solar masses can leave the event horizon rapidly?The black holes merged to form a new, even larger black hole of about 142 solar masses, emitting the energetic equivalent of eight solar masses in the process
I understand that these are very energetic; but I was of the impression that, other than hawking radiation (which doesn't technically *leave* the black hole) nothing returns to the universe from past the event horizon other than gravity.
Energy can be siphoned from a black hole with lasers.
Gravitational waves cause a loss of mass?Was this mass not within the event horizon to begin with? Or is there a mechanism by which 8 solar masses can leave the event horizon rapidly?The black holes merged to form a new, even larger black hole of about 142 solar masses, emitting the energetic equivalent of eight solar masses in the process
I understand that these are very energetic; but I was of the impression that, other than hawking radiation (which doesn't technically *leave* the black hole) nothing returns to the universe from past the event horizon other than gravity.
Actually the 8 solar masses of energy are in the form of gravitational waves.
That's a slingshot; stealing inertia from a black hole. That does not actually pull any mass from within the event horizon.Was this mass not within the event horizon to begin with? Or is there a mechanism by which 8 solar masses can leave the event horizon rapidly?The black holes merged to form a new, even larger black hole of about 142 solar masses, emitting the energetic equivalent of eight solar masses in the process
I understand that these are very energetic; but I was of the impression that, other than hawking radiation (which doesn't technically *leave* the black hole) nothing returns to the universe from past the event horizon other than gravity.
Energy can be siphoned from a black hole with lasers.
EDIT: https://www.youtube.com/watch?v=ZevUW__aMZE
Gravitational waves cause a loss of mass?Was this mass not within the event horizon to begin with? Or is there a mechanism by which 8 solar masses can leave the event horizon rapidly?The black holes merged to form a new, even larger black hole of about 142 solar masses, emitting the energetic equivalent of eight solar masses in the process
I understand that these are very energetic; but I was of the impression that, other than hawking radiation (which doesn't technically *leave* the black hole) nothing returns to the universe from past the event horizon other than gravity.
Actually the 8 solar masses of energy are in the form of gravitational waves.
Mass-energy conversion is generally bi-directional (in theory at least)... mass converted to energy creates energy that could be converted to mass.
Since gravity itself is not created by the conversion of mass into energy, do you have a source I could look at to understand how gravitational waves *are* the result of mass-energy conversion?
If so, how is this energy immune to gravity (IOW, can escape)?
A system of black holes orbiting a giant black hole in a gas disk sounds like something straight out of Lensman sci-fi. So ridiculously over the top it's hard to think about it being real.
That's a slingshot; stealing inertia from a black hole. That does not actually pull any mass from within the event horizon.Was this mass not within the event horizon to begin with? Or is there a mechanism by which 8 solar masses can leave the event horizon rapidly?The black holes merged to form a new, even larger black hole of about 142 solar masses, emitting the energetic equivalent of eight solar masses in the process
I understand that these are very energetic; but I was of the impression that, other than hawking radiation (which doesn't technically *leave* the black hole) nothing returns to the universe from past the event horizon other than gravity.
Energy can be siphoned from a black hole with lasers.
EDIT: https://www.youtube.com/watch?v=ZevUW__aMZE
It depends on what the actual mass of the star is.A "solar" system of black holes - not pleasant, I'm sure. Also, If a collapsing star isn't of sufficient mass to form a black hole, doesn't it form a neutron star? I'm at coloring book level with this stuff.
I'm not sure there is a difference. A photon has a mass of ~0, but are we saying that there's zero higgs interaction? If I turned an entire star into photons, and contained all those photons in a space the size of the star, there would be no gravity from that space? That feels counter-intuitive.That's a slingshot; stealing inertia from a black hole. That does not actually pull any mass from within the event horizon.Was this mass not within the event horizon to begin with? Or is there a mechanism by which 8 solar masses can leave the event horizon rapidly?The black holes merged to form a new, even larger black hole of about 142 solar masses, emitting the energetic equivalent of eight solar masses in the process
I understand that these are very energetic; but I was of the impression that, other than hawking radiation (which doesn't technically *leave* the black hole) nothing returns to the universe from past the event horizon other than gravity.
Energy can be siphoned from a black hole with lasers.
EDIT: https://www.youtube.com/watch?v=ZevUW__aMZE
Not quite. It would be if this was dealing with accelerating an object with mass around the BH. The interaction with the BH in this case is done strictly with light.
I'm not sure there is a difference. A photon has a mass of ~0, but are we saying that there's zero higgs interaction? If I turned an entire star into photons, and contained all those photons in a space the size of the star, there would be no gravity from that space? That feels counter-intuitive.That's a slingshot; stealing inertia from a black hole. That does not actually pull any mass from within the event horizon.Was this mass not within the event horizon to begin with? Or is there a mechanism by which 8 solar masses can leave the event horizon rapidly?The black holes merged to form a new, even larger black hole of about 142 solar masses, emitting the energetic equivalent of eight solar masses in the process
I understand that these are very energetic; but I was of the impression that, other than hawking radiation (which doesn't technically *leave* the black hole) nothing returns to the universe from past the event horizon other than gravity.
Energy can be siphoned from a black hole with lasers.
EDIT: https://www.youtube.com/watch?v=ZevUW__aMZE
Not quite. It would be if this was dealing with accelerating an object with mass around the BH. The interaction with the BH in this case is done strictly with light.
It wouldn't be a star anymore but... why is it impossible? What law of physics prevents that many photons from being in that small a space?I'm not sure there is a difference. A photon has a mass of ~0, but are we saying that there's zero higgs interaction? If I turned an entire star into photons, and contained all those photons in a space the size of the star, there would be no gravity from that space? That feels counter-intuitive.Not quite. It would be if this was dealing with accelerating an object with mass around the BH. The interaction with the BH in this case is done strictly with light.
That's correct, *if* indeed you could have a star consisting only of photons which isn't possible.
It wouldn't be a star anymore but... why is it impossible? What law of physics prevents that many photons from being in that small a space?I'm not sure there is a difference. A photon has a mass of ~0, but are we saying that there's zero higgs interaction? If I turned an entire star into photons, and contained all those photons in a space the size of the star, there would be no gravity from that space? That feels counter-intuitive.Not quite. It would be if this was dealing with accelerating an object with mass around the BH. The interaction with the BH in this case is done strictly with light.
That's correct, *if* indeed you could have a star consisting only of photons which isn't possible.
It wouldn't be a star anymore but... why is it impossible? What law of physics prevents that many photons from being in that small a space?I'm not sure there is a difference. A photon has a mass of ~0, but are we saying that there's zero higgs interaction? If I turned an entire star into photons, and contained all those photons in a space the size of the star, there would be no gravity from that space? That feels counter-intuitive.Not quite. It would be if this was dealing with accelerating an object with mass around the BH. The interaction with the BH in this case is done strictly with light.
That's correct, *if* indeed you could have a star consisting only of photons which isn't possible.
I wasn't being clear. You're correct that photons lack mass, so any density of photons (a "star-like" configuration or otherwise) will also lack mass.
The gravity waves form outside the event horizons of the black holes and move in all directions at the speed of light. They don't escape from inside the event horizon.Gravitational waves cause a loss of mass?Was this mass not within the event horizon to begin with? Or is there a mechanism by which 8 solar masses can leave the event horizon rapidly?The black holes merged to form a new, even larger black hole of about 142 solar masses, emitting the energetic equivalent of eight solar masses in the process
I understand that these are very energetic; but I was of the impression that, other than hawking radiation (which doesn't technically *leave* the black hole) nothing returns to the universe from past the event horizon other than gravity.
Actually the 8 solar masses of energy are in the form of gravitational waves.
Mass-energy conversion is generally bi-directional (in theory at least)... mass converted to energy creates energy that could be converted to mass.
Since gravity itself is not created by the conversion of mass into energy, do you have a source I could look at to understand how gravitational waves *are* the result of mass-energy conversion?
If so, how is this energy immune to gravity (IOW, can escape)?
That goes back to my original question.The gravity waves form outside the event horizons of the black holes and move in all directions at the speed of light. They don't escape from inside the event horizon.Gravitational waves cause a loss of mass?
Mass-energy conversion is generally bi-directional (in theory at least)... mass converted to energy creates energy that could be converted to mass.
Since gravity itself is not created by the conversion of mass into energy, do you have a source I could look at to understand how gravitational waves *are* the result of mass-energy conversion?
If so, how is this energy immune to gravity (IOW, can escape)?
It wouldn't be a star anymore but... why is it impossible? What law of physics prevents that many photons from being in that small a space?I'm not sure there is a difference. A photon has a mass of ~0, but are we saying that there's zero higgs interaction? If I turned an entire star into photons, and contained all those photons in a space the size of the star, there would be no gravity from that space? That feels counter-intuitive.Not quite. It would be if this was dealing with accelerating an object with mass around the BH. The interaction with the BH in this case is done strictly with light.
That's correct, *if* indeed you could have a star consisting only of photons which isn't possible.
Put another way: Convert the entire universe to photons and there's no gravity anywhere anymore?
The last explanation I had (from relativity) was that a photon travels in a straight line, but the fabric of spacetime is curved by gravity. Similarly, an event horizon represented a point at which the curvature came back on itself (think of the inside of a sphere); such that there was no spacial path out (no direction represents "away" from the singularity at that point).It wouldn't be a star anymore but... why is it impossible? What law of physics prevents that many photons from being in that small a space?I'm not sure there is a difference. A photon has a mass of ~0, but are we saying that there's zero higgs interaction? If I turned an entire star into photons, and contained all those photons in a space the size of the star, there would be no gravity from that space? That feels counter-intuitive.Not quite. It would be if this was dealing with accelerating an object with mass around the BH. The interaction with the BH in this case is done strictly with light.
That's correct, *if* indeed you could have a star consisting only of photons which isn't possible.
I wasn't being clear. You're correct that photons lack mass, so any density of photons (a "star-like" configuration or otherwise) will also lack mass.
I always thought that gravitational lensing was because photons do have some mass... or is it just how spacetime is curved? wait, I'm no longer sure what mass actually is. Crap... back to wikipedia...
It's a though experiment. It seems to be how most modern theories began, from relativity to thermodynamics.It wouldn't be a star anymore but... why is it impossible? What law of physics prevents that many photons from being in that small a space?
Put another way: Convert the entire universe to photons and there's no gravity anywhere anymore?
whew, that's a pretty tall order!
who's gonna do this , you and who else???
no disrespect intended, but imaginations have been known to yield some fantastic movies!
What's the difference?That's a slingshot; stealing inertia from a black hole. That does not actually pull any mass from within the event horizon.Was this mass not within the event horizon to begin with? Or is there a mechanism by which 8 solar masses can leave the event horizon rapidly?The black holes merged to form a new, even larger black hole of about 142 solar masses, emitting the energetic equivalent of eight solar masses in the process
I understand that these are very energetic; but I was of the impression that, other than hawking radiation (which doesn't technically *leave* the black hole) nothing returns to the universe from past the event horizon other than gravity.
Energy can be siphoned from a black hole with lasers.
EDIT: https://www.youtube.com/watch?v=ZevUW__aMZE
Photons are lensed because space(time) is curved, not because photons have mass.At this early juncture in our ability to detect gravitational waves many events will be records of some kind or another. Still, this event stands out in a number of ways. Re photon mass, obviously photons must have mass or they would not be gravitationally lensed. Isn't their mass related to their wavelength?
It wouldn't be a star anymore but... why is it impossible? What law of physics prevents that many photons from being in that small a space?I'm not sure there is a difference. A photon has a mass of ~0, but are we saying that there's zero higgs interaction? If I turned an entire star into photons, and contained all those photons in a space the size of the star, there would be no gravity from that space? That feels counter-intuitive.Not quite. It would be if this was dealing with accelerating an object with mass around the BH. The interaction with the BH in this case is done strictly with light.
That's correct, *if* indeed you could have a star consisting only of photons which isn't possible.
I wasn't being clear. You're correct that photons lack mass, so any density of photons (a "star-like" configuration or otherwise) will also lack mass.
I always thought that gravitational lensing was because photons do have some mass... or is it just how spacetime is curved? wait, I'm no longer sure what mass actually is. Crap... back to wikipedia...
It wouldn't be a star anymore but... why is it impossible? What law of physics prevents that many photons from being in that small a space?I'm not sure there is a difference. A photon has a mass of ~0, but are we saying that there's zero higgs interaction? If I turned an entire star into photons, and contained all those photons in a space the size of the star, there would be no gravity from that space? That feels counter-intuitive.Not quite. It would be if this was dealing with accelerating an object with mass around the BH. The interaction with the BH in this case is done strictly with light.
That's correct, *if* indeed you could have a star consisting only of photons which isn't possible.
I wasn't being clear. You're correct that photons lack mass, so any density of photons (a "star-like" configuration or otherwise) will also lack mass.
How much mass did Jupiter lose when Voyager used it as a slingshot?What's the difference?That's a slingshot; stealing inertia from a black hole. That does not actually pull any mass from within the event horizon.
Mass is energy. A good chunk of the "mass" of baryons is just the kinetic energy of quarks and the strong force interactions between them.
So your statement is that there was 8 solar masses of potential energy and that potential energy was creating gravity (had mass)? And that potential energy became gravity waves (which don't have mass?) Or did I miss something?A tiny but significant amount of "mass" in atomic nuclei is weak force interactions within the nuclei. That's how the whole "mass deficit=energy released" thing works.
A system of black holes is no different in that regard. As the black holes fall closer together, they trade gravitational potential for kinetic energy. As they orbit around one another, they trade kinetic energy for gravitational wave emissions. As energy eaves the system through gravitational waves, the "mass" of the entire system decreases, not the mass of either black hole.
I've seen theoretical processes for stealing rotational energy from a solitary black hole as well.
Would the Kugelblitz black hole result in the photons converting back into matterr? Or would the photons convert to mass for some other reason thus causing it? Or do massless items have gravity?It wouldn't be a star anymore but... why is it impossible? What law of physics prevents that many photons from being in that small a space?I'm not sure there is a difference. A photon has a mass of ~0, but are we saying that there's zero higgs interaction? If I turned an entire star into photons, and contained all those photons in a space the size of the star, there would be no gravity from that space? That feels counter-intuitive.Not quite. It would be if this was dealing with accelerating an object with mass around the BH. The interaction with the BH in this case is done strictly with light.
That's correct, *if* indeed you could have a star consisting only of photons which isn't possible.
I wasn't being clear. You're correct that photons lack mass, so any density of photons (a "star-like" configuration or otherwise) will also lack mass.
This is incorrect. While photons lack mass they still have energy, and will still cause distortion of spacetime. In fact, it is theorized that we could create tiny black holes called Kugelblitz black holes by shining a large number of very powerful and focussed lasers through a microscopic region of space.
It depends on what you mean by mass.At this early juncture in our ability to detect gravitational waves many events will be records of some kind or another. Still, this event stands out in a number of ways. Re photon mass, obviously photons must have mass or they would not be gravitationally lensed. Isn't their mass related to their wavelength?
That goes back to my original question.The gravity waves form outside the event horizons of the black holes and move in all directions at the speed of light. They don't escape from inside the event horizon.Gravitational waves cause a loss of mass?
Mass-energy conversion is generally bi-directional (in theory at least)... mass converted to energy creates energy that could be converted to mass.
Since gravity itself is not created by the conversion of mass into energy, do you have a source I could look at to understand how gravitational waves *are* the result of mass-energy conversion?
If so, how is this energy immune to gravity (IOW, can escape)?
8 solar masses was lost. Where did that 8 solar masses reside prior to being lost? Did it reside inside the event horizon (meaning there's a way to reduce the mass of a black hole), or was it already outside the event horizon (an accretion disk for example), in which case "nothing to see here".
I'm not who that was to, but based on the "firing a laser around a black hole" assertion, I have to conclude that photons can exchange energy (via gravity) with an object (a black hole) in order to preserve concervation of energy.It depends on what you mean by mass.
They certainly don't require any rest mass, and the assumption "no mass=no gravitational interaction" is false even in Newtonian mechanics, where the acceleration due to gravity is independent of the mass (or lack thereof) of any object being accelerated by the gravitational field.
While it's true that there's a mass dependence for the force on an object in a gravitational field, there's also a mass dependence for the acceleration in terms of the force (F=ma), and when you combine the equations they cancel one another exactly.
You can certainly make the argument that photons in motion have energy and therefore mass due to mass-energy equivalence, but saying they must have mass to be affected by gravity is fallacy.
OK. But we started with mass, yes?I'll try to find and add a reasonably readable link - if I can find one - to this post later if I get a chance but the source of "mass" in a black hole is space-time curvature itself (there actually isn't just one way to define the mass of a black hole but the usual way is as mass equivalence as determined a very long way away (technically, at infinity) from the black hole). In General Relativity (and Black Holes are creatures of GR so at least for now it's all we've got) it isn't really correct to think of a Black Hole like a classical object with some mass at the center causing the gravity. In the case of black holes, it's probably best to (by analogy) think of a black hole as being not the hole at the center of a whirlpool but the whirlpool itself. The way that this is often stated is that a black hole's mass is everywhere. SO don't think of a black hole as some mass concentrated at the center and the gravity somehow getting out. The spacetime curvature is all there is.
That's my understanding. Massenergy that interacts with the higgs field cannot move a C and is called "mass". Massenergy that does not interact with the higgs field is called "energy" and can only move a C.Also, remember that mass-energy equivalence means literally that. Whatever they are - if they are anything beyond just energy being a mathematical property which must be locally conserved for purely mathematical reasons - in other words, energy may not be a thing in itself but just a thing we define because it is useful to describe things) mass and energy are the same thing.
I believe am the person who mentioned that.Lastly, someone above mentioned this... Gravity doesn't pull on things. Photons are affected by spacetime curvature because they are traveling on what passes for straight lines in curved spacetime (called geodesics). Just like on the surface of a sphere, there is literally no such thing as a straight line a curved surface - a straight line would have to leave the surface of the sphere. Since photons can't leave spacetime and spacetime is curved by mass/energy/momentum then a photon's path will curve just like an airplane following the curve of the Earth as it flies.
OK. But we started with mass, yes?I'll try to find and add a reasonably readable link - if I can find one - to this post later if I get a chance but the source of "mass" in a black hole is space-time curvature itself (there actually isn't just one way to define the mass of a black hole but the usual way is as mass equivalence as determined a very long way away (technically, at infinity) from the black hole). In General Relativity (and Black Holes are creatures of GR so at least for now it's all we've got) it isn't really correct to think of a Black Hole like a classical object with some mass at the center causing the gravity. In the case of black holes, it's probably best to (by analogy) think of a black hole as being not the hole at the center of a whirlpool but the whirlpool itself. The way that this is often stated is that a black hole's mass is everywhere. SO don't think of a black hole as some mass concentrated at the center and the gravity somehow getting out. The spacetime curvature is all there is.
So if I have 100 solar masses of whirlpool, and I didn't put 100 solar masses of mass and energy into it to make that, then there's "new" mass (or so it seems from your analogy). That would seem to be a problem.
That's my understanding. Massenergy that interacts with the higgs field cannot move a C and is called "mass". Massenergy that does not interact with the higgs field is called "energy" and can only move a C.Also, remember that mass-energy equivalence means literally that. Whatever they are - if they are anything beyond just energy being a mathematical property which must be locally conserved for purely mathematical reasons - in other words, energy may not be a thing in itself but just a thing we define because it is useful to describe things) mass and energy are the same thing.
I believe am the person who mentioned that.Lastly, someone above mentioned this... Gravity doesn't pull on things. Photons are affected by spacetime curvature because they are traveling on what passes for straight lines in curved spacetime (called geodesics). Just like on the surface of a sphere, there is literally no such thing as a straight line a curved surface - a straight line would have to leave the surface of the sphere. Since photons can't leave spacetime and spacetime is curved by mass/energy/momentum then a photon's path will curve just like an airplane following the curve of the Earth as it flies.
Though it also turn out that gravity has a speed (specifically: gravity travels at c); and I *think* quantum is trying to move us to an understanding of a "gravity field" more than Einstein's curved spacetime; but I'm way above my paygrade here.